How to get path and filename from postman request body using Go

Question

This question already asked but it is not solve my issue.

In my Go project am not able to print path and filename. It is showing some error like below:

2021/10/13 16:25:07 http: panic serving [::1]:60170: runtime error: invalid memory address or nil pointer dereference goroutine 6 [running]:

My Postman collection

my code

package main

import (
    "fmt"
    "net/http"

    "github.com/gorilla/mux"
)

func encodeFfmpeg(w http.ResponseWriter, r *http.Request) {
    w.Header().Set("Content-Type", "multipart/form-data")
    _, header, _ := r.FormFile("video")
    fmt.Println(header.Filename)
}

func main() {
    router := mux.NewRouter()

    router.HandleFunc("/encode", encodeFfmpeg).Methods("POST")

    // config port
    fmt.Printf("Starting server at 8080 \n")
    http.ListenAndServe(":8080", router)
}

Am trying to print filename with path eg: /home/ramesh/videos/video.mp4

`FormFile` returns an error. Check the error *before* touching any of the other values returned by `FormFile`. If the error is not `nil` then `header` will most likely be `nil` and the expression `header.Filename` *will* panic. — mkopriva, Oct 13 '21 at 11:08
Setting `w.Header().Set("Content-Type", "multipart/form-data")` will not modify `r` in any way. It makes no sense whatsoever to have it there unless you are also responding with a payload, i.e. writing a response body, of that specific content type. — mkopriva, Oct 13 '21 at 11:09
@mkopriva: I added ` _, header, err := r.FormFile("video") if err != nil { panic(err) } ` it shows this error `http: panic serving [::1]:60476: no multipart boundary param in Content-Type goroutine 6 [running]:` — Ramesh S, Oct 13 '21 at 11:20
That means that the `boundary` parameter in the `Content-Type` header of the Postman request is missing. This parameter is required for `multipart/form-data` to work properly. See this [answer](https://stackoverflow.com/questions/16015548/how-to-send-multipart-form-data-request-using-postman) (the boundary is mentioned at the bottom). — mkopriva, Oct 13 '21 at 11:24
@mkopriva: I added the `boundary` like this `Content-Type:multipart/form-data;boundary=` please check this image https://ibb.co/GnhJMgj. But still showing same error — Ramesh S, Oct 13 '21 at 11:49
The linked answer, its associated comments, and the other answers too, suggest that you should keep Content-Type unset, and leave it to Postman to set it automatically. [This](https://i.stack.imgur.com/vA0se.png) in the second answer has the heading *"Fails If In Header"*. [This](https://i.stack.imgur.com/08wZj.png) has the heading *"Works"*. — mkopriva, Oct 13 '21 at 11:56
You are right now I removed `Content-Type` now it is working. Please add this as a answer I will give upvote and right tick — Ramesh S, Oct 13 '21 at 11:58

score 2 · Accepted Answer · answered Oct 13 '21 at 12:04

The sent request is missing the boundary parameter in the Content-Type header. This parameter is required for multipart/form-data to work properly.

In Postman remove the explicit Content-Type header setting and leave it to Postman to automatically set the header with the boundary parameter.

For more see: https://stackoverflow.com/a/16022213/965900 & https://stackoverflow.com/a/41435972/965900

Last but not least, do not ignore errors.

Thanks for the answer it is working – Ramesh S Oct 13 '21 at 12:05 — Ramesh S, Oct 13 '21 at 12:05

How to get path and filename from postman request body using Go

1 Answers1