I start learning python, and in an exercise it asks to create a program that only postive intger number will be accepted.
This is what I have written:
while True:
number = input('Type an integer positive number: ')
try:
number = int(number)
break
except ValueError:
print ('Value not accepted')
break
How can I add in my block the >0 check ?
You could throw an exception using raise.
while True:
number = input('Type an integer positive number: ')
try:
number = int(number)
if number < 0 :
raise ValueError
except ValueError:
print ('Value not accepted')
break
Output
Type an integer positive number: 3
Type an integer positive number: 4
Type an integer positive number: -4
Value not accepted
You should try to check if is bigger than 0 before the first break.
while True:
number = input('Type an integer positive number: ')
try:
number = int(number)
if number > 0:
break
except ValueError:
print ('Value not accepted')
break
I'm guessing you wanna keep your exception handling as it is so my suggestion would be:
while True:
number = input('Type an integer positive number: ')
try:
number = int(number)
if number <= 0:
raise ValueError('Negative number or zero entered.')
break
except ValueError as ve:
print(ve)
break
I hope this helps you to finish your task and you continue to have fun learning Python. I'm also new to this but Python is so much fun! :)
use continus to let user input again.
while True:
number = input('Type an integer positive number: ')
try:
number = int(number)
if number < 0:
continue
else:
break
except ValueError:
print('Value not accepted')
break
