extract last portion from url

Question

Having the following link: /C:\Users\xxx\Desktop\yyy\public\assets\1634648850202.jpg

How do i extract 1634648850202.jpg?

i tried:

const lastplace = thisUrl.substring(thisUrl.lastIndexOf("\"));

This does not work, because the backslash is recognized as a functional character (is this the right term?)

Here are 2 Questions from my side:

1. how do i extract the last part?
2. how should i handle backslashes in general?

Answer 1

Common way:

thisUrl.split(/\/|\\/).pop() // 1634648850202.jpg

I also recommend to split url/path by both slashes (/,\) 'cause of different enviromnents/systems uses diffrent character.

UPD: just make your \ double to handle it (you're right, it's a escape character), like this:

''.lastIndexOf('\\')

Also you need do the same when you initiate your string:

const thisUrl = '/C:\\Users\\xxx\\Desktop\\yyy\\public\\assets\\1634648850202.jpg';