Why is parsing an XML file going wrong?

Asked Oct 20 '21 at 11:36

Active Oct 20 '21 at 11:36

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I have an XML reader application who reads through thousands of XML files, during the processing I received the following error: xml.etree.ElementTree.ParseError: not well-formed (invalid token): line 62, column 48

After debugging I found out its file_348.xml which is presented in below code. Now I don't know what's wrong with this XML file, when I open it manually I receive the same error. Is it a corrupt error? What I want is my application to ignore these kind of bad XML files and go on with the ones that are readable. If you have any other workarounds I Would like to hear them

import xml.etree.ElementTree as ET

path = 'C:/data/UserA/Desktop//XML-files/file_348.xml'

tree = ET.parse(path)

print(tree)

asked Oct 20 '21 at 11:36

Andalusia

This might help https://stackoverflow.com/questions/13046240/parseerror-not-well-formed-invalid-token-using-celementtree – Linux Geek Oct 20 '21 at 11:41
2

You can attempt to parse the file in a *try/except* construct and just *pass* if an exception is raised to ignore it – Oct 20 '21 at 11:48
@ Linux Geek Already tried that but the recover variable is not longer usable for `ET.parse()` – Andalusia Oct 20 '21 at 11:48
Perhaps you could show that code and someone will be able to help you – Oct 20 '21 at 12:08
Looks like `file_348.xml` is not a valid xml doc. Can you share it? – balderman Oct 20 '21 at 12:45
@BrutusForcus, thats what I did. thank you bro. – Andalusia Oct 21 '21 at 07:38
@Andalusia I wasn't clear. My mistake. What I meant was... show the XML data – Oct 21 '21 at 07:45
@BrutusForcus I meant to say that the try/except thing solved my problem bro. I cant show any XML data because its classified :( – Andalusia Oct 21 '21 at 07:48

Why is parsing an XML file going wrong?

0 Answers0