how can i match strings, if one of them are not complete equal?

Question

i have two arrays and i want to verify to synchronic both, if in both existe the same name that should be stored in the array and the others no

for example: i need all the objects with name rea.jpg but in my array i have like this ['dsjajdsj...h2/rea.jpg']
this is the materials

[{name: 'hgb.jpg' }, { name: 'rea.jpg'}, {  name: 'ca.png' }]

the file extension is always the end of the string

i want to verify if exist an object in the names's array

const names = ['h2/rea.jpg']
const materials = [{
  name: 'hgb.jpg'
}, {
  name: 'rea.jpg'
}, {
  name: 'ca.png'
}]
const res = materials.filter(x => names.includes(x.name))
console.log('RES', res)

expected result shoud be [ {name: 'rea.jpg'}]

Your `names` array has fully-qualified filenames (with paths) and I'm assuming you don't want to compare the path component, just the filename, so why not create a second array that has just the filenames from `names`? Then your filter code will work. — jarmod, Oct 22 '21 at 14:14
@jarmod How can I create that list of names without making any mistakes with this character / ? — bruce lee, Oct 22 '21 at 14:16
See https://stackoverflow.com/questions/19811541/nodejs-get-file-name-from-absolute-path/55311046 — jarmod, Oct 22 '21 at 14:19
@jarmod i wont like to install a library or unless its too necesary? — bruce lee, Oct 22 '21 at 14:24
The 'path' library is part of Node.js (assuming this is Node.js). — jarmod, Oct 22 '21 at 14:29

ProDec · Answer 1 · 2021-10-22T14:23:02.920

1

Use Array#some to pass in a custom compare function.

const names = ['h2/rea.jpg']
const materials = [{
  name: 'hgb.jpg'
}, {
  name: 'rea.jpg'
}, {
  name: 'ca.png'
}]
const res = materials.filter(x => names.some(y => y.endsWith('/' + x.name)))
console.log('RES', res)

edited Oct 22 '21 at 14:23

answered Oct 22 '21 at 14:17

ProDec

5,390
1
3
12

Will incorrectly match `law/mens-rea.jpg` etc. – jarmod Oct 22 '21 at 14:21
revised to add leading / – ProDec Oct 22 '21 at 14:24
The updated code will be OK if the `names` array elements *always* include a path. – jarmod Oct 22 '21 at 14:26
original question said so – ProDec Oct 22 '21 at 14:26
if names and materials are not in fixed pattern, it ends with no solution. – ProDec Oct 22 '21 at 14:29

score 1 · Answer 2 · answered Oct 22 '21 at 14:23

const names = ['h2/rea.jpg']
const materials = [{
  name: 'hgb.jpg'
}, {
  name: 'rea.jpg'
}, {
  name: 'ca.png'
}]
const res = materials.filter(x => {
    const ni = names.filter(ni => ni.includes(x.name))
    return ni.length > 0
})
console.log(res)

But if names is long and you don't want to iterate over it on every element of materials follow the other suggestion and transform names to only include the filename.

const fnames = names.map(ni => ni.split('/')[ni.split('/').length-1])
const res = materials.filter(x => names.includes(x.name))
console.log(res)

score 1 · Answer 3 · answered Oct 22 '21 at 14:35

Use some inside of the filter to acheive this (note, this will run in O(n^2)).

const names = ['h2/rea.jpg']
const materials = [{
  name: 'hgb.jpg'
}, {
  name: 'rea.jpg'
}, {
  name: 'ca.png'
}]
const res = materials.filter(x => names.some(y => y.endsWith('/' + x.name)))

console.log('RES', res)

score 1 · Accepted Answer · answered Oct 22 '21 at 14:40

Assuming this is Node.js, you can use the path library to convert the fully-qualified pathnames to simple filenames, then do your includes test. For example:

const path = require('path');

const pathnames = ['h2/rea.jpg'];
const filenames = pathnames.map((x) => path.basename(x));

const materials = [
  {
    name: 'hgb.jpg',
  },
  {
    name: 'rea.jpg',
  },
  {
    name: 'ca.png',
  },
];

const res = materials.filter((x) => filenames.includes(x.name));
console.log('RES', res);
// RES [ { name: 'rea.jpg' } ]

score 1 · Answer 5 · answered Oct 22 '21 at 14:55

If you like it oldscool, then with two loops and Regex.

const names = ['h2/rea.jpg']
const materials = [{
    name: 'hgb.jpg'
  }, 
  {
    name: 'rea.jpg'
  }, 
  {
    name: 'ca.png'
  }]

  const res = [];

materials.forEach((x) => {
    let search = x.name    
    let reg = new RegExp(search, 'g');
    let match = '';
    names.forEach((n) => {
      match = n.match(reg);
    })
    if(match) {
      res.push(x)
    }  
})

console.log('RES', res)

how can i match strings, if one of them are not complete equal?

5 Answers5