I'm fairly new to python and I'm trying to understand I do I loop regex groups, ex:
reobj = re.compile('<a href="(.*?)">(.*?)</a>', re.IGNORECASE)
result = reobj.findall(body)
how do I loop the 2 groups from the regex ? Thanks!
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Pedro Lobito
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1What do you mean, "loop the groups"? What are you trying to achieve? – Daniel Roseman Aug 07 '11 at 09:19
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the regex matches 2 groups (.*?) and I want to loop both groups. – Pedro Lobito Aug 07 '11 at 09:22
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3Considering your example, you may also be interested in http://stackoverflow.com/questions/1732348/regex-match-open-tags-except-xhtml-self-contained-tags – Thomas Wouters Aug 07 '11 at 10:00
2 Answers
6
Did you actually try this in the shell?
>>> body = """<a href="http://foo.com">Foo</a><br><a href="http://bar.com">Bar</a>"""
>>> reobj = re.compile('<a href="(.*?)">(.*?)</a>', re.IGNORECASE)
>>> result = reobj.findall(body)
>>> result
[('http://foo.com', 'Foo'), ('http://bar.com', 'Bar')]
So the result of findall is simply a list of tuples containing the matched groups. If you don't know how to iterate through a list, then you need to do an introductory Python tutorial.
[insert standard rant about how you shouldn't use regex to parse HTML here...]
Daniel Roseman
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The answer I needed was:
reobj = re.compile('<a href="(.*?)">(.*?)</a>', re.IGNORECASE)
result = reobj.findall(body)
for link in result:
print link[0] + link[1]
Pedro Lobito
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