>>>a='11111111111111111111111111110101'
>>>int(a,2)
4294967285
In the above code, I thought that 32'nd number is MSB(Most Significant Bit) and if MSB is 1,
The value indicates negative.
but why does the int() function return positive number?
Asked
Active
Viewed 81 times
0
John Kugelman
- 349,597
- 67
- 533
- 578
Kernel_Handler
- 21
- 3
-
6Python `int` is an arbitrary-precision type, not a 32-bit signed integer type. – user2357112 Oct 29 '21 at 01:52
-
Try setting `a` to `'-11111111111111111111111111110101'` – kindall Oct 29 '21 at 01:55
1 Answers
2
In Python that works a bit different, it is using two complements. I think the answer to the question here is what you are looking for and answers the 'why?'. You can test that yourself by using the bin()-function which returns you the bit equivalent of a number.
a='11111111111111111111111111110101'
print(int(a,2))
#4294967285
# Postive Integer
# Same as above
b='0b11111111111111111111111111110101'
print(int(b,2))
#4294967285
# Negative Integer
=c'-0b11111111111111111111111111110101'
print(int(c,2))
#-4294967285
David
- 116
- 2
- 10