Your current command is almost there, instead off using xargs
with grep
, lets:
- Move the
grep
to an -exec
- Use
xargs
to pass the result to dirname
to show only the parent folder
find ./ -maxdepth 2 -type f -exec grep -l "foo-bundle" {} /dev/null \; | xargs dirname
If you only want to search for composer.json
files, we can include the -iname
option like so:
find ./ -maxdepth 2 -type f -iname '*composer.json' -exec grep -l "foo-bundle" {} /dev/null \; | xargs dirname
If the | xargs dirname
doesn't give enough data, we can extend it so we can loop over the results of find
using a while read
like so:
find ./ -maxdepth 2 -type f -iname '*composer.json' -exec grep -l "foo-bundle" {} /dev/null \; | while read -r line ; do
parent="$(dirname ${line%%:*})"
echo "$parent"
done
We can use grep to search for all files containing a specific text.
After looping over each line, we can
- Remove behind the
:
to get the filepath
- Use
dirname
to get the parent folder path
Consider this file setup, were /test/b/composer.json
contains foo-bundle
➜ /tmp tree
.
├── test
│ ├── a
│ │ └── composer.json
│ └── b
│ └── composer.json
└── test.sh
When running the following test.sh
:
#!/bin/bash
grep -rw '/tmp/test' --include '*composer.json' -e 'foo-bundle' | while read -r line ; do
parent="$(dirname ${line%:*})"
echo "$parent"
done
The result is as expected, the path to folder b
:
/tmp/test/b