How to use SED to extract string

Question

I am very new to sed.

I wanted to extract the id from

{ "requestId": "aee4f0cd-4b15-4df5-ab6b-62874963105a" }

and return aee4f0cd-4b15-4df5-ab6b-62874963105a.

How do I do it using sed ?

That looks like JSON. A parser like [tag:jq] would be a better fit. `echo '{ "requestId": "aee4f0cd-4b15-4df5-ab6b-62874963105a" }' | jq -r '.requestId'` — 0stone0, Oct 29 '21 at 13:29
Does this answer your question? [Non greedy (reluctant) regex matching in sed?](https://stackoverflow.com/questions/1103149/non-greedy-reluctant-regex-matching-in-sed) — gkhaos, Oct 29 '21 at 13:30
Does this answer your question? [Parsing JSON with Unix tools](https://stackoverflow.com/questions/1955505/parsing-json-with-unix-tools) — 0stone0, Oct 29 '21 at 13:51

score 2 · Answer 1 · answered Oct 29 '21 at 13:32

2

jq is better:

s='{ "requestId": "aee4f0cd-4b15-4df5-ab6b-62874963105a" } '

echo "$s" | jq '.requestId'
"aee4f0cd-4b15-4df5-ab6b-62874963105a"

Or, no quotes:

echo "$s" | jq -r '.requestId'
aee4f0cd-4b15-4df5-ab6b-62874963105a

answered Oct 29 '21 at 13:32

dawg

score 1 · Accepted Answer · answered Oct 29 '21 at 13:30

1

Using jq is a better solution, but by sed you should apply this:

echo '{ "requestId": "aee4f0cd-4b15-4df5-ab6b-62874963105a" }' | sed -r 's/^.*: "(.+)".*$/\1/'

answered Oct 29 '21 at 13:30

Antonio Petricca

2 Answers2