Python different case implementing question

Asked Oct 29 '21 at 20:21

Active Oct 29 '21 at 20:21

Viewed 24 times

Can someone help me get test number 5 implemented into my code where it prints the first eight numbers then it goes to another line prints the next 8 and so on!

numbers = [
   int(input("Enter n1: ")),
   int(input("Enter n2: "))
]

new_list = [ ]
def numbers_counter(n1,n2):
    if n1 > n2:
        pattern = ""
        pattern = f"Invalid value for n2"
    elif n1 == n2:
        pattern = ""
        pattern = (f"{n1}")
    elif n2 > n1:
        for i in range(n1, n2, 2):
            pattern = i
            new_list.append(pattern)
    return pattern,new_list
pattern,new_list = numbers_counter(n1 = numbers[0],n2 = numbers[1])


if numbers[0] > numbers[1] or numbers[0] == numbers[1]:
    print(pattern)
elif numbers[1] > numbers[0]:
    for i in new_list:
        print(i,end= " ")

asked Oct 29 '21 at 20:21

mirrat rashid

2

FYI you can combine `>` and `==` with `>=`. – Barmar Oct 29 '21 at 20:23
1

What's the problem? Loop from n1 to n2, have a counter ++ and print a newline every 8 numbers – Thomas Weller Oct 29 '21 at 20:26
1

See https://stackoverflow.com/questions/312443/how-do-you-split-a-list-into-evenly-sized-chunks for how to group the list into chunks of 8. Print each chunk on one line. – Barmar Oct 29 '21 at 20:26
Thank you will take that into account, can you help me how i can implement those cases in python! – mirrat rashid Oct 29 '21 at 20:26
Are you sure that's not because of a style and the task is to print all even numbers between to numbers? – Einliterflasche Oct 29 '21 at 20:27
1

FYI, you don't need the loop. `new_list = list(range(n1, n2, 2))` – Barmar Oct 29 '21 at 20:28
I am not sure whats the actual thing you are asking but that code should print "40, 42, 44, 46, 48, 50, 52, 54" as you asked, have you ran this code yourself? – aberkb Oct 29 '21 at 20:28
you can also do this `numbers_counter(numbers[0],numbers[1])` since you're passing the value to the function. – stefan_aus_hannover Oct 29 '21 at 20:28
@ThomasWeller how would i implemnt that? I am confused about that – mirrat rashid Oct 29 '21 at 20:28
1

@Barmar `n2+1`? – It_is_Chris Oct 29 '21 at 20:29
1

@stefan_mit_hannover ik i like doing it this way tho! – mirrat rashid Oct 29 '21 at 20:29
@It_is_Chris The loop uses `n2`, not `n2+1`. – Barmar Oct 29 '21 at 20:30
@Barmar oops you're correct. I was thinking `list(range(numbers[0], numbers[1]+1, 2))` – It_is_Chris Oct 29 '21 at 20:32
Can anyone help i am so confused – mirrat rashid Oct 29 '21 at 20:36

Python different case implementing question

0 Answers0