Moving up directory to access file not using raw path in Python

Question

I have a project named testrequest and I am working on a file named test_function_pack.py. The working code within the said file is below:

service = Service(r'C:\user\Dev\Selenium\testrequest\drivers\chromedriver.exe')

I wish to try accessing the chromedriver.exe file using .. or . dots and by my understanding, the distance of the two file is two directories upward. I tested using the below code

import os
os.chdir('..')
service = Service(r'../../drivers/chromedriver.exe')

But the code above does not work, am I missing anything here? Any help is appreciated.

Here is the folder by the way:

https://stackoverflow.com/a/65333932/9928905 You can use this piece of code by that you can automate the process of configuring the chromedriver to the latest version — Rajath Rao - Software Engineer, Jan 04 '22 at 11:11

score 1 · Answer 1 · answered Oct 30 '21 at 11:21

1

I guess something like this should work.

import os
stepups = 2
a = '/'.join(os.path.dirname(__file__).split('\\')[:stepups]) + '/drivers/chromedriver.exe'
print(a)

Do your own work regarding the step-ups you require, and change that accordingly.

answered Oct 30 '21 at 11:21

Ankan Das

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Thanks for this answer, in my case I need to set my `stepups` to 5 to achieve the correct path. It's amazing that it is able to navigate to the right folder. – KiritoLyn Oct 30 '21 at 11:41
Glad I could help! – Ankan Das Oct 31 '21 at 13:03

Moving up directory to access file not using raw path in Python

1 Answers1