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For example, I have an array like this. Here there are array objects for the same date and different values.

[
    {
        "date": "2020-12-31T18:30:00.000Z",
        "value": 450
    },
    {
        "date": "2020-12-31T18:30:00.000Z",
        "value2": 362
    },
    {
        "date": "2020-12-31T18:30:00.000Z",
        "value3": 699
    },
    {
        "date": "2021-03-01T18:30:00.000Z",
        "value": 269
    },
    {
        "date": "2021-03-01T18:30:00.000Z",
        "value2": 450
    },
    {
        "date": "2021-03-02T18:30:00.000Z",
        "value3": 841
    },
    {
        "date": "2021-04-03T18:30:00.000Z",
        "value": 700
    },
]

I want to make an array grouped and merged for the date as below. The different values with the same "date" are merged into one array object.

[
    {
        "date": "2020-12-31T18:30:00.000Z",
        "value": 450,
        "value2": 362,
        "value3": 699
    },
    {
        "date": "2021-03-01T18:30:00.000Z",
        "value": 269,
        "value2": 450
    },
    {
        "date": "2021-03-02T18:30:00.000Z",
        "value3": 841
    },
    {
        "date": "2021-04-03T18:30:00.000Z",
        "value": 700
    }
]
Jenish MS
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    Does this answer your question? [Most efficient method to groupby on an array of objects](https://stackoverflow.com/questions/14446511/most-efficient-method-to-groupby-on-an-array-of-objects) – Tobias S. Nov 02 '21 at 03:58

1 Answers1

0

You can efficiently achieve the result using Map and reduce

const arr = [
  {
    date: "2020-12-31T18:30:00.000Z",
    value: 450,
  },
  {
    date: "2020-12-31T18:30:00.000Z",
    value2: 362,
  },
  {
    date: "2020-12-31T18:30:00.000Z",
    value3: 699,
  },
  {
    date: "2021-03-01T18:30:00.000Z",
    value: 269,
  },
  {
    date: "2021-03-01T18:30:00.000Z",
    value2: 450,
  },
  {
    date: "2021-03-02T18:30:00.000Z",
    value3: 841,
  },
  {
    date: "2021-04-03T18:30:00.000Z",
    value: 700,
  },
];

const dict = arr.reduce((acc, curr) => {
  const { date, ...rest } = curr;
  if (!acc.has(date)) {
    acc.set(date, curr);
  } else {
    const o = acc.get(curr.date);
    Object.entries(curr).forEach(([k, v]) => (o[k] = v));
  }
  return acc;
}, new Map());

const result = [...dict.values()];

console.log(result);
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  max-height: 100% !important;
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DecPK
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