How can I turn the format yyyy-mm-ddThh:mm:ss to a unix timestamp?

Question

I'm returning information from an API and it uses this format to send timestamps, is there any easy way to return this time as Unix? It returns as a string and all the methods i've tried so far don't work. Thank you for any help

It's been aswered [here](https://stackoverflow.com/questions/19801727/convert-datetime-to-unix-timestamp-and-convert-it-back-in-python) — pyzer, Nov 04 '21 at 07:26
@pyzer it returns the timestamp as a string, how could I work with that? — DreamLogic, Nov 04 '21 at 07:33
Does this answer your question? [How do I parse an ISO 8601-formatted date?](https://stackoverflow.com/questions/127803/how-do-i-parse-an-iso-8601-formatted-date) — moooeeeep, Nov 04 '21 at 08:08
@moooeeeep msh gave me a similar answer below, thanks though! — DreamLogic, Nov 05 '21 at 02:03

score 0 · Accepted Answer · answered Nov 04 '21 at 07:47

Let's say somehow you got the time as YYY-mm-ddTHH:MM:SS format.

To convert from string to a time object you can use:

from datetime import datetime

t = datetime.strptime("2021-11-4T10:44:00", "%Y-%m-%dT%H:%M:%S")

Now you have a datetime object which you can use to do as you wish. For example you want to convert it to unix time format (which @pyzer shared as a comment)?

t.timestamp()

How can I turn the format yyyy-mm-ddThh:mm:ss to a unix timestamp?

1 Answers1