-1

I'm fetching pokemon names and images, and storing them like this.

   const pokemon = $(el)
      .find(".pokemon")
      .toArray()
      .map((el) => {
        const name = $(el).attr("title") || "";
        const image = $(el).find("img").attr("src") || "";
        return { name, image };
      });

I want a seperate variable that sorts by most reoccurring and then removes duplicates. I tried using byCount() from this:

Array.prototype.byCount = function () {
  var itm,
    a = [],
    L = this.length,
    o = {};
  for (var i = 0; i < L; i++) {
    itm = this[i];
    if (!itm) continue;
    if (o[itm] == undefined) o[itm] = 1;
    else ++o[itm];
  }
  for (var p in o) a[a.length] = p;
  return a.sort(function (a, b) {
    return o[b] - o[a];
  });
};

and it worked if i fetch the name / image separately, but doesn't seem to work on an object. the data is like

[name1, name1, name2, name3, name3, name4]
[img1, img1, img2, img3, img3, img4]

if i sort them individually using byCount() they don't always align so it might return:

[name1, name3, name2, name4]
[img3, img1, img2, img4]

since both img1 & img3 have the same occurance count.

Liam
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Liiaam93
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  • Does this answer your question? [Remove duplicate in a string - javascript](https://stackoverflow.com/questions/35609731/remove-duplicate-in-a-string-javascript) – Liam Nov 04 '21 at 09:08
  • 1
    Better duplicate [Get all unique values in a JavaScript array (remove duplicates)](https://stackoverflow.com/questions/1960473/get-all-unique-values-in-a-javascript-array-remove-duplicates) – Liam Nov 04 '21 at 09:08

2 Answers2

1
const repeatedItems = {}
arrayOfObjects.forEach((item) => {
  if (repeatedItems[item.name]) {
    repeatedItems[item.name] = { ...item, count: repeatedItems[item.name].count++ }
  } else {
    repeatedItems[item.name] = { ...item, count: 1 }
  }
})
const sortedArr = Object.values(repeatedItems).sort((a, b) => a.count - b.count).map((item) => ({ name: item.name, image: item.image }))
Alopwer
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-1

To sort words with the prototype sort, use the localeCompare String prototype:


items.sort((a, b) => a.localeCompare(b))

Aviv Ben Shahar
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