I want to print int in multi-line
Here is my python code:
a=int(3)
b=int(5)
c=a+b,"\n",a-b,"\n",a*b,"\n"
print(c)
Output I want to achieve:
8
-2
15
Output I'm getting:
(8, '\n', 2, '\n', 15, '\n')
Will someone help me out with this?
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SushantUniversity
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2`print(a + b, a - b, a * b, sep='\n')`… – deceze Nov 08 '21 at 14:36
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Are you looking for ``print(*c)``? – MisterMiyagi Nov 08 '21 at 14:40
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can you explain your answer how this working? because it's working – SushantUniversity Nov 08 '21 at 14:47
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what does ```print(*c)``` do? – SushantUniversity Nov 08 '21 at 14:54
4 Answers
1
a=3
b=3
c=str(a+b)+"\n" + str(a-b) + "\n" + str(a*b) + "\n"
print(c)
Try this one.
Chamoda De silva
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You could iteratively print the elements of c.
a = int(3)
b = int(5)
c = a+b, a-b, a*b
for i in c:
print(i)
Bashton
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yes bro this is what I want is it any way to do this without loop? – SushantUniversity Nov 08 '21 at 14:43
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In that case, why not just store each calculation as an indivual variable? – Bashton Nov 08 '21 at 15:09
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when writing :
c = a+b,"\n",a-b,"\n",a*b,"\n"
you actually creating a tuple, separated by commas,
that's why when printing this is the output you get. this is why @Bashton answer require iterations on c (as a list)
if you with replace the commas with + you actually create one string concatenated (by + signs). that's why when you print it only takes one print. that's why
c=str(a+b)+"\n" + str(a-b) + "\n" + str(a*b) + "\n"
solution would only require one print.
learningtocode
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sorry, i met tuple, and of course tuple is also iterable. fixed my answer, thanks – learningtocode Nov 08 '21 at 14:48
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@SushantUniversity Look [here](https://docs.python.org/3.10/library/stdtypes.html#tuples): _"Tuples may be constructed in a number of ways: ... Separating items with commas: `a, b, c` ..."_ – Timus Nov 08 '21 at 14:55