C Time Function

Question

Hi I want to printf the dateApp function

For example I expected : 19:04 But the result is : 19:4

How to modify the function, so the function always return 2 digits, Thankyou!

void dateApp(){
    char line[500] = "\xb3";
    time_t currentTime;
    time(&currentTime);
    struct tm *myTime = localtime(&currentTime);
    printf("Date : %i/%i/%i       \xb3 Time : %i:%i %44s", myTime ->tm_mday, myTime->tm_mon + 1, myTime->tm_year + 1900, myTime->tm_hour, myTime->tm_min, line );
}

use `%02i` (percent zero two i) instead of `%i` – Ronald Nov 10 '21 at 13:13 — Ronald, Nov 10 '21 at 13:13

score 1 · Accepted Answer · answered Nov 10 '21 at 13:16

1

You need to add a field width of 2 to each %i if you want it to always print at least 2 characters, along with the 0 flag to tell it to pad with zeros on the left.

printf("Date : %02i/%02i/%i       \xb3 Time : %i:%02i %44s", ...

answered Nov 10 '21 at 13:16

dbush

205,898
23
218
273

C Time Function

1 Answers1