Why "51" > "6" is false in JavaScript
"51" > "1" = true
"51" > "2" = true
"51" > "3" = true
"51" > "4" = true
"51" > "5" = true
But the below one is false,
"51" > "6" = false
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Kavin
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5Because `"5"` is less than `"6"`. – tkausl Nov 12 '21 at 06:37
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Adding to @tkausl's comment, you shouldn't compare numbers as strings. You will ALWAYS run into issues. Just do parseFloat() – GoldenretriverYT Nov 12 '21 at 06:39