Parallel.Invoke same action executed

Asked Nov 12 '21 at 08:26

Active Nov 12 '21 at 08:32

Viewed 172 times

I'm tryng to execute some actions in parallel:

public static void Main()
{
    var actions = new List<Action>();
    for (int i = 0; i < 10; i++)
    {
        actions.Add(() => DoSomething(i));
    }
    
    Parallel.Invoke(actions.ToArray());
}

private static void DoSomething(int number)
{
    Console.WriteLine(string.Format("DoSomething number {0}", number));
    Thread.Sleep(5000);
}

But only the last action, with number parameter equals to 10 executed. In the output I got 10 times the same value:

DoSomething number 10

Click here for fiddle example

asked Nov 12 '21 at 08:26

user3607621

What is the actual value of `i` when the actions are executed? 10. This has nothing to do with `Parallel.Invoke`. Although using `Parallel.Invoke` like this is highly unusual. You probably need `Parallel.ForEach` instead – Panagiotis Kanavos Nov 12 '21 at 08:27
You are closing over the loop variable – TheGeneral Nov 12 '21 at 08:28
1

https://dotnetfiddle.net/6SzKlJ – TheGeneral Nov 12 '21 at 08:29
Try use `Parallel.For(0, 10, (i) => DoSomething(i));` instead. – Auditive Nov 12 '21 at 08:32

Parallel.Invoke same action executed

0 Answers0