The way every recursive version has an iterative version as well is this right saying that vice-versa is also true (i.e. every iterative version has recursive version)?
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1Does this answer your question? [Can all iterative algorithms be expressed recursively?](https://stackoverflow.com/questions/2093618/can-all-iterative-algorithms-be-expressed-recursively) – eglease Nov 12 '21 at 15:23