Awaiting a void function in javascript

Question

Hi I was wondering how I could await a void function. I tried the following (mock up):

async function asyncer() {
  setTimeout(() => {
    console.log("async msg")
  }, 0)
}

async function helloer() {
  await asyncer()
  console.log("hello")
}

helloer()

This however doesn't work, so I tried the following :

async function asyncer() {
  setTimeout(() => {
    console.log("async msg")
  }, 0)
  return true
}

async function helloer() {
  let ready = await asyncer()
  if (ready) {
    console.log("hello")
  }
}

helloer()

Still "hello" is still logged before "async msg". Does anyone know a solution to this problem. Thanks in advance.

use `Promise` see here for more detail https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Promise — Alen.Toma, Nov 18 '21 at 22:32
setTimeout doesn't block. `await` is for promises, of which there are none here. Please check the [docs](https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Operators/await) — Phix, Nov 18 '21 at 22:33

score 0 · Accepted Answer · answered Nov 18 '21 at 22:42

0

async/await is a syntax sugar for promise.then, so create a Promise.resolve or smth to enter in async flow and then use async/await

answered Nov 18 '21 at 22:42

Vadim Bilyy

34
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Awaiting a void function in javascript

1 Answers1