How to use random function to get values from an interval

Question

So basically i got this function

Math.random()

we were taught to use this formula in order to get values from 1 to x

parseInt(Math.random()*x)+1;

but now what i want to do is to get values from x to y but i'm not sure how to do it .. any help ?

@SagarV how come? it seems to work on my end.. the only assumption is that `y > x` — The Bomb Squad, Nov 19 '21 at 19:38
@TheBombSquad for example, if you want to get a number between 12 and 25, the above code, `parseInt(Math.random()*25)+12` can generate upto 36. `parseInt(0.99 * 25)+12` — Sagar V, Nov 19 '21 at 19:41
ah.. you're right ;-; tnx it would be `parseInt(Math.random()*(y-x))+x` my bad — The Bomb Squad, Nov 19 '21 at 22:16

score 0 · Answer 1 · answered Nov 19 '21 at 19:48

0

const doRandom = (min,max) => {
return Math.floor(Math.random() * (max - min) + min);
}

console.log(doRandom(5,9));

answered Nov 19 '21 at 19:48

Joshua Craven

1 Answers1