Comparing strings with the format "2.0.1", "2.0.09"

Question

I need to get the user's app version number and compare it with the current app version on my server. If the user's app version is lower, then he will get a pop-up to update his app. While doing this, I need to compare the version of the app with the versions that are available. How can I compare the strings which are in the format "2.0.1" and "2.0.09" and get the highest one, in Objective-C?

Answer 1

How about using the compare:options: method of the NSString class?

NSString *v1 = @"2.0.1";
NSString *v2 = @"2.1";

NSComparisonResult result = [v1 compare:v2 options:NSNumericSearch];
if (result == NSOrderedSame || result == NSOrderedDescending) {
    // do
} else {
    // do
}

Answer 2

If your strings are all of the form "2.0.1" etc. you can just compare them as is with the right options:

([localVersionString compare:currentVersionString
                     options:NSNumericSearch] != NSOrderedAscending);

The above would return "YES" if the localVersion is no older than the currentVersion on the server, and "NO" otherwise (assuming I have this the right way round).

This is the usual thing to do when checking the local version of iOS installed on an iDevice.

Answer 3

As answered in this post; Compare version numbers in Objective-C

Check out my NSString category that implements easy version checking on github; https://github.com/stijnster/NSString-compareToVersion

[@"1.2.2.4" compareToVersion:@"1.2.2.5"];

This will return a NSComparisonResult which is more accurate than using;

[@"1.2.2" compare:@"1.2.2.5" options:NSNumericSearch]

Helpers are also added;

[@"1.2.2.4" isOlderThanVersion:@"1.2.2.5"];
[@"1.2.2.4" isNewerThanVersion:@"1.2.2.5"];
[@"1.2.2.4" isEqualToVersion:@"1.2.2.5"];
[@"1.2.2.4" isEqualOrOlderThanVersion:@"1.2.2.5"];
[@"1.2.2.4" isEqualOrNewerThanVersion:@"1.2.2.5"];