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I want to send a url like this (below)
http://localhost:8080/adminProjectsViewAll#projectDetailsModal

but how to send it from a Spring Boot Controller

My application.properties :

spring.mvc.view.prefix=/views/
spring.mvc.view.suffix=.jsp

spring.datasource.url=jdbc:mysql://localhost:3306/test3
spring.datasource.username=user1
spring.datasource.password=pass
spring.jpa.hibernate.ddl-auto=update

## Hibernate Properties
# The SQL dialect makes Hibernate generate better SQL for the chosen database
spring.jpa.properties.hibernate.dialect = org.hibernate.dialect.MySQL5InnoDBDialect

#server.servlet.context-path=/ems
Turnus Silver
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  • Does this answer your question? [How to get the URL fragment identifier from HttpServletRequest](https://stackoverflow.com/questions/13503213/how-to-get-the-url-fragment-identifier-from-httpservletrequest) – xerx593 Nov 22 '21 at 20:17
  • No I have to Send It from controller to the View @xerx593 – Turnus Silver Nov 23 '21 at 17:44

0 Answers0