How can i get three recieving messages from socket server instead two?

Asked Nov 23 '21 at 12:40

Active Nov 23 '21 at 12:40

Viewed 30 times

Hi guys i cant figure out why socket server sends me second message with the third one at the same time. However I want to get message one by one not together at the same time. How can i do this? Server code:

import socket

host = socket.gethostbyname(socket.gethostname())
port = 5000
ADDR = (host, port) 
s = socket.socket(socket.AF_INET,
                  socket.SOCK_STREAM)
s.bind(ADDR)
s.listen()
c, addr = s.accept()  
c.send(b'7:S ACK:4,')
c.send(b'11:S END:kSfdy,')
c.send(b'8:S 120794,')

Client code:

import socket

HOST = '192.168.1.54'  # The server's hostname or IP address
PORT = 5000
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.connect((HOST, PORT))
print(s.recv(1024))
print(s.recv(1024))
print(s.recv(1024))    #empty message

asked Nov 23 '21 at 12:40

GGGGGG

https://stackoverflow.com/a/43420503/238704 – President James K. Polk Nov 23 '21 at 13:15
@PresidentJamesK.Polk so there is no need to do that? Socket always send me second message with other N - messages? – GGGGGG Nov 23 '21 at 15:58
@PresidentJamesK.Polk I read the page but i dont understand it well. Can you explain it to me? – GGGGGG Nov 23 '21 at 16:16
1

@GGGGGG the send calls and the recv calls are ***completely unrelated*** and when you call recv the operating system could give you a random amount of data – user253751 Nov 23 '21 at 17:13
@user253751 random? But when i just call recv function it gives me nothing. – GGGGGG Nov 23 '21 at 20:10
@GGGGGG because the second call got all the data already and there isn't any left? – user253751 Nov 23 '21 at 21:28

How can i get three recieving messages from socket server instead two?

0 Answers0