Trying to write a function that receives a number argument and check and print if the number is positive, negative, or zero (Python 3)

Question

Here is my code to check is the number is positive, negative or zero.

x = input("Enter a number to check if it is positive, negative or zero.")
def function():
    if x == 0:
    print("The number is zero.")
    
    elif x > 0: 
    print("The number is positive.")
    
    elif x < 0:
    print("The number is negative.")

Here is the error I get

File "<string>", line 4
    print("The number is zero.")
    ^
IndentationError: expected an indented block
>

Indentation is very important in Python. Have you written any Python code before? If not, I recommend you learn the basic syntax first. — , Nov 26 '21 at 18:31
... This is NOT a function receiving an integer argument ... — Patrick Artner, Nov 26 '21 at 18:32
Thanks, I just learned not to ignore the error feedbacks I get. — Inverted_ Spaces, Nov 26 '21 at 18:59
I fixed the code def fun(): x =input("Enter a number to check if it is positive,negative or zero:") if int(x) == 0: print("The number is zero.") elif int(x) > 0: print("The number is positive.") elif int(x) < 0: print("The number is negative.") fun() — Inverted_ Spaces, Nov 26 '21 at 19:00

score 0 · Accepted Answer · answered Nov 26 '21 at 18:30

0

Indentation is very important in Python:

if x == 0:
    print("The number is zero.")

answered Nov 26 '21 at 18:30

Trying to write a function that receives a number argument and check and print if the number is positive, negative, or zero (Python 3)

Here is my code to check is the number is positive, negative or zero.

1 Answers1