convert a dict into a (const) tuple of tuples

Question

I want to convert a dict to a tuple of tuples

from typing import Dict, Tuple
class Data:
    def __init__(self, d: Dict[int, str]) -> None:
        self.data: Tuple[Tuple[int, str], ...] = ()
        for k, v in d.items():
            self.data += ((k, v),)

d = Data({5: "five", 4: "four"})
print(d.data)

This is somewhat similar to this question, but not identical. The reason I prefer a tuple of tuples is for const-ness. Is there a better way (or more pythonic) to achieve this?

score 2 · Answer 1 · answered Nov 28 '21 at 09:14

2

You could do tuple(d.items()).

answered Nov 28 '21 at 09:14

rchome

2,623
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score 1 · Answer 2 · answered Nov 28 '21 at 09:19

1

Try this:

myDict = {5:"five",4:"four"}

def dictToTuple(d):
   return tuple(d.items())

print(dictToTuple(myDict))

answered Nov 28 '21 at 09:19

Finlay

108
10

score 1 · Accepted Answer · answered Nov 28 '21 at 09:41

1

It seems that this question is probably a duplicate of this, and the fourth answer there (@Tom) states it's fastest to do tuple construction of list comprehension:

self.data: Tuple[Tuple[int, str], ...] = tuple([(k, v) for k, v in d.items()])

answered Nov 28 '21 at 09:41

OrenIshShalom

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convert a dict into a (const) tuple of tuples

3 Answers3