How to use FastJson to go from Json string to Object Collection

Question

I am using fastJSON and I ran into a problem. I cannot take a JSON string and convert it to a collection of objects.

I thought it could handle this but maybe I am doing it wrong or misunderstood.

Handles polymorphic collections of objects

Here is an example I did in a C# cmd line app (just download the .cs files and add to a project and copy the follow code to test).

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;

namespace ConsoleApplication1
{
    class Program
    {
        static void Main(string[] args)
        {
            List<Class1> store = new List<Class1>();
            for (int i = 0; i < 3; i++)
            {
                Class1 c = new Class1();
                c.Name = "test";
                c.Start = DateTime.Now;
                store.Add(c);
            }

           string jsonResult = fastJSON.JSON.Instance.ToJSON(store);

           List<Class1> backToObject = fastJSON.JSON.Instance.
               ToObject<List<Class1>>(jsonResult);
        }
    }

    public class Class1
    {
        public string Name { get; set; }
        public DateTime Start { get; set; }
    }
}

backToObject is always null.

I am using fastJSON because I need something that really has no dependencies on .NET libraries and I am using monodroid (and probably later monotouch) and it is very picky in what you can use and can't use.

For instance I can not use the Json.net library (I think there is one for monodroid but I trying to make my code reusable for when I do the iPhone part).

Does Monodroid support the dynamic keyword? If so, you could use my parser FridayThe13th: http://procbits.com/2011/08/11/fridaythe13th-the-best-json-parser-for-silverlight-and-net/ It doesn't use any nonstandard .NET libraries. — JP Richardson, Aug 11 '11 at 19:44
Oh, oops.. I just realized that you want to Serialize and object and not Deserialize a JSON string. FridayThe13th doesn't support that yet. — JP Richardson, Aug 11 '11 at 19:46

steve cook · Answer 1 · 2014-06-12T13:03:01.083

5

Note that as of fastJSON 2.x, the OP code should basically work fine (note that the syntax has changed slightly).

List<Class1> wallets = JSON.ToObject<List<Class1>>(json);

edited Jun 12 '14 at 13:03

answered Jun 08 '14 at 08:51

steve cook

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casperOne · Accepted Answer · 2011-08-11T14:33:24.040

You shouldn't use ToObject to deserialize an array. Instead, you should use the Parse method to parse the JSON.

When using ToObject, you are assuming that you have an instance of an object in JSON that is being deserialized (not an array, or a scalar value), with Parse, it will handle any type that is serialized into JSON and return the appropriate type.

In this case, calling Parse and passing jsonResult to it will return an ArrayList which contains the three instances:

ArrayList arrayList = fastJSON.JSON.Instance.parse(jsonResult) as ArrayList;

The problem with that is that now you have an ArrayList containing a number of Dictionary<string, object> instances which have the the scalar values (or other Dictionary<string, object> instances, in the case of references) mapped to the property name.

I'd classify this as a bug. I'd expect the parsing of an array to handle this correctly.

You could modify the code for ParseArray to sniff the type when the call to array.Add is made.

That still leaves an issue with ParseNumber (which could potentially be called) returning a string. This might or might not impact you.

I'd make whatever changes you need as well as file an issue with the issue tracker on the CodePlex project site.

How to use FastJson to go from Json string to Object Collection

2 Answers2