Specific random number range

Question

I want to generate random float number in the range 0 and 0.0001

I tried:

from numpy import random
random.random(0, 0.0001)

But i got the error :

TypeError: random() takes at most 1 positional argument (2 given)

Then i tried :

 from numpy import random
 random.random(0.0001)

But i got the error : TypeError: 'float' object cannot be interpreted as an integer

How can i produce random numbers in this range ? [0, 0.0001]

Does this answer your question? [How to get a random number between a float range?](https://stackoverflow.com/questions/6088077/how-to-get-a-random-number-between-a-float-range) — Mark Dickinson, Dec 03 '21 at 12:27
`np.random.random` docs specify only one argument, the `size`, number of returned values. Range [0,1) is fixed. When getting errors like this, your **first** stop should be the function documentation. If it still isn't clear, then ask us :) — hpaulj, Dec 03 '21 at 17:16

score 2 · Answer 1 · edited Dec 03 '21 at 12:20

2

you can use random.uniform like this

import random

print(random.uniform(0, 0.0001))

edited Dec 03 '21 at 12:20

Mark Dickinson

answered Dec 03 '21 at 08:52

ttdat-thecodeguy

score 2 · Answer 2 · edited Dec 03 '21 at 12:19

2

You can make use of random.uniform to generate a float number between the given value.

import numpy as np
print(np.random.uniform(0, 0.0001))

edited Dec 03 '21 at 12:19

Mark Dickinson

answered Dec 03 '21 at 08:59

iamniki

score 1 · Answer 3 · edited Dec 03 '21 at 14:29

1

To get around this issue, you can generate a random number between 0 and 1 and divide the result by 10000.

from numpy import random
random.random() / 10000

edited Dec 03 '21 at 14:29

Mark Dickinson

answered Dec 03 '21 at 08:49

ahammond

3 Answers3