I have code like this in a "foo.py":
# -*- coding: utf-8 -*-
import multiprocessing as mp
def foo():
return 2
ctx = mp.get_context("forkserver")
process = ctx.Process(target=foo, args=())
process.start()
if I run python foo.py
, it will raise Exception like this:
raise RuntimeError('''
RuntimeError:
An attempt has been made to start a new process before the
current process has finished its bootstrapping phase.
This probably means that you are not using fork to start your
child processes and you have forgotten to use the proper idiom
in the main module:
if __name__ == '__main__':
freeze_support()
...
The "freeze_support()" line can be omitted if the program
is not going to be frozen to produce an executable.
I do know how to avoid this, if I change to like this:
import multiprocessing as mp
def foo():
return 2
if __name__ == "__main__":
ctx = mp.get_context("forkserver")
process = ctx.Process(target=foo, args=())
process.start()
It works fine, but I want to know why should I need to put code to main
block? what freeze_support
means?
python==3.8.5