creating and naming multiple lists with a for-loop

Question

I have a list that contists of several elements:

list = ["a", "b", "c", "d", "e", "f", "g"]

I need a for-loop, that generates multiple lists, that contain all of the elements exept for one element and also want to name them appropriately. It should look something like this:


for i in list:
    globals()['list_' + str(i)] = list.remove(i)

The result should look like this:

list_a = ["b", "c", "d", "e", "f", "g"]
list_b = ["a", "c", "d", "e", "f", "g"]
list_c = ["a", "b", "d", "e", "f", "g"] 
list_d = ["a", "b", "c", "e", "f", "g"]
ect...

**Do not do this**. Use *a container*, like another `list`, or porbably a `dict` here. Don't dynamically modify variables. — juanpa.arrivillaga, Dec 06 '21 at 20:31
Note, `list.remove(i)` *returns `None`*, why did you expect something else? You'll have to build a new list. Note, you should never modify a list while you iterate over it — juanpa.arrivillaga, Dec 06 '21 at 20:32

Erik McKelvey · Answer 1 · 2021-12-06T20:54:21.130

1

You can use a dictionary:

lst = ["a", "b", "c", "d", "e", "f", "g"]
dic = {}
for item in lst:
    dic['list_' + item] = [x for x in lst if not x == item]
print(dic)

Output:

{'list_a': ['b', 'c', 'd', 'e', 'f', 'g'], 'list_b': ['a', 'c', 'd', 'e', 'f', 'g'], 'list_c': ['a', 'b', 'd', 'e', 'f', 'g'], 'list_d': ['a', 'b', 'c', 'e', 'f', 'g'], 'list_e': ['a', 'b', 'c', 'd', 'f', 'g'], 'list_f': ['a', 'b', 'c', 'd', 'e', 'g'], 'list_g': ['a', 'b', 'c', 'd', 'e', 'f']}

edited Dec 06 '21 at 20:54

answered Dec 06 '21 at 20:33

Erik McKelvey

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Don't use the name `dict` - it will override a builtin. – alani Dec 06 '21 at 20:34

creating and naming multiple lists with a for-loop

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