How to remove duplicates from a list whilst preserving order?

Question

If I have a list like this: lst = ['a','a','b','a', 'a', 'c', 'c', 'c','d','e','a', 'b', 'b', 'b'],

when I am apply set(lst), it will remove all the duplicates. But I only wanna remove the consistently duplicates and keep the rest of then in order, so my ideal output is ['a', 'b','a', 'c', 'd', 'e', 'a', 'b']

Any help would be really appreciated!

Shorthand version of groupby solution: `[*next(zip(*groupby(lst)))]` — Alain T., Dec 07 '21 at 00:29

score 2 · Accepted Answer · answered Dec 06 '21 at 22:43

2

from itertools import groupby

lst = ['a','a','b','a', 'a', 'c', 'c', 'c','d','e','a', 'b', 'b', 'b']

print([key for key, _ in groupby(lst)])

answered Dec 06 '21 at 22:43

Paul M.

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How to remove duplicates from a list whilst preserving order?

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