Why code:
hl = [[]]*3
hl[0].append(1)
return hl
gives [[1],[1],[1]] instead of [[1],[],[]]?
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1because `hl = [[]]*3` creates a list with three references *to the same empty list*. The same as if you did `empty = []; hl = [empty, empty, empty]` – juanpa.arrivillaga Dec 09 '21 at 00:44
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1A solution: `hl = [[] for _ in range(3)]` – juanpa.arrivillaga Dec 09 '21 at 00:45