Converting a Seq[Int] to a tuple with predetermined size, in Scala

Question

So I have a Sequence of Ints representing notes on a guitar, now since this guitar will have 6 strings, I also have a function parameter that takes 6 Ints in a tuple like this:

pos: (Int, Int, Int, Int, Int, Int)

After have looked for "Scala seq to tuple" on Google and having found nothing useful I ask here.

How do I pass my Seq[Int] as a tuple into my function parameter most effectively?

Answer 1

Can you avoid the Seq in the first place and have a Tuple since the very beginning?

If not, the best you can do is pattern match the Seq

seq match {
  case Seq(n1, n2, n3, n4, n5, n6) => Some(f((n1, n2, n3, n4, n5, n6)))
  case _ => None
}