How to get terminate or run code after a line that is blocking the code and does not pass command to next line?

Question

I am trying to get the IP address and other details of Linux through my python code. when tmp = subprocess.call("./a.out") this line executes the code sticks here and this line subprocss.call("ifconfig") is not executed. as I cannot change the C code. so how can I make the next line run.

def execute():
    dirname = '/home/kali/Downloads'
    ext = ('.py','.c','.sh')
    try:
        for files in os.listdir(dirname):
            if files.endswith(ext):
                if files.endswith('.c'):
                    subprocess.call(["gcc", "code.c"])
                    tmp = subprocess.call("./a.out")
                    subprocss.call("ifconfig")

For non-blocking `subprocess.call`: https://stackoverflow.com/questions/16071866/non-blocking-subprocess-call — tueda, Dec 09 '21 at 17:02
The bug is in ```code.c``` -- look there to see why it doesn't return — AbbeGijly, Dec 09 '21 at 17:03
actually, code.c elevates the privileges and make me root user now the root terminal pops up and block the rest code — Hassan Turi, Dec 09 '21 at 17:06

score -1 · Accepted Answer · answered Feb 03 '23 at 08:38

-1

I got answer for this question after a long time of research. It can be done with a function subprocess.communicate function. this function can communicate with the process.

answered Feb 03 '23 at 08:38

Hassan Turi

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How to get terminate or run code after a line that is blocking the code and does not pass command to next line?

1 Answers1