Removing defaultdict from print statement

Question

So I have a custom function that returns a default dict. This is how the value is currently returned as:

defaultdict(<function multi_level_dict at 0x0000014E2E099A60>, {'a': 1, 'b': 2})

How can I turn this value into:

{'a': 1, 'b': 2}

Preferably without using a for/while loop.

use `dict(your_default_dict)`. Note that it is really not necessary in order to work with the defaultdict. — buran, Dec 10 '21 at 16:57
You could make a subclass of `defaultdict` that replaces the stringification logic with that of `dict`. This will work even for the recursive case. — o11c, Dec 10 '21 at 18:06

score 1 · Accepted Answer · answered Dec 10 '21 at 16:57

You can construct a regular dict from a defaultdict:

>>> d
defaultdict(<class 'int'>, {'a': 1, 'b': 2})
>>> dict(d)
{'a': 1, 'b': 2}

Note that if the dict is nested such that some of the values are themselves defaultdicts, converting the top level dict won't do anything to those nested values.

Removing defaultdict from print statement

1 Answers1