underscore.each will complete cycle instead await inside

Question

I've a _each() that inside got an await where I check a user state in MySQL

the mysql response return after cycle is already completed. there is a way that wait the method checkUserState(), beforse and than go to next element of _each()?

 let obj = _.each(guest_list.guests, async function (value){
     let user_state = await DataController.checkUserState('2305');
    value.Owner.state = user_state;
    console.log('state:' + user_state);
    return value;
  });

  console.log('cycle complete')
 return obj;

Result is: cycle complete state:notdisturb state:notdisturb state:notdisturb state:notdisturb state:notdisturb state:notdisturb state:notdisturb state:notdisturb state:notdisturb state:notdisturb state:notdisturb state:notdisturb

abhishek sahu · Accepted Answer · 2021-12-17T13:49:02.500

0

You need to use Promise.all

let obj = await Promise.all(_.map(guest_list.guests, async function (value){
     let user_state = await DataController.checkUserState('2305');
    value.Owner.state = user_state;
    console.log('state:' + user_state);
    return value;
  }));

  console.log('cycle complete')
 return obj;

edited Dec 17 '21 at 13:49

answered Dec 17 '21 at 13:40

abhishek sahu

648
4
8

_.each does not return an array, this is not going to work – Nikita Mazur Dec 17 '21 at 13:43
is the same of my code, cycle finish before await – Mariano Dec 17 '21 at 13:44
@RogerAI you need to _.map function instead of each or you need to use for loop. – abhishek sahu Dec 17 '21 at 13:48
Updated my answer as well please check now. – abhishek sahu Dec 17 '21 at 13:49

underscore.each will complete cycle instead await inside

1 Answers1