project local coordinates to global GPS with reference point

Question

I have a bunch of shapes (e.g. shapely LineStrings or Polygons) in a geopandas GeoDataFrame. The shapes specify coordinates in a local 200x200 meters grid, i.e. all coordinates are between (0, 0) and (200, 200).

I now would like to "place" these lines globally. For this, I want to specify a GPS Point (with a given lat/lon) as a reference.

My first (naive) approach would be to use geographiclib, take all shapes' coords (in local X/Y) and apply the following transformation and "recreate" the shape:

# Convert coordinates to GPS location
from shapely.geometry import LineString
from geographiclib.geodesic import Geodesic
geod = Geodesic.WGS84  # the base geodesic (i.e. the world)

origin = (48.853772345870176, 2.350983211585546)  # this is somewhere in Paris, for example

def local_to_latlong(x, y, orientation=0, scale=1):
    """ Two step process.
    - First walk x meters to east from origin.
    - Then, from that point, walk y meters north from origin.
    
    Optional: 
    - orientation allows to "spin" the coordinates
    - scale allows to grow/shrink the distances
    """
    go_X = geod.Direct(*origin, orientation + 90, x * scale)  # x is East-coordinate
    go_Y = geod.Direct(go_X["lat2"], go_X["lon2"], orientation + 0, y * scale)  # y is North-coordinate
    return go_Y["lat2"], go_Y["lon2"]


original_line = LineString([(0,0), (100,100), (200,100)])
global_line = LineString([local_to_latlong(x, y) for y, x in original_line.coords])

However, I hope that this is not the smartest way to do it, and that there are smarter ways out there...

I would like to apply such a transformation onto any shape within a GeoDataFrame. Ideally, it would work using a "to_crs", but I am not sure how to transform the shapes so they are "in reference to a origin" and which crs to use.

You statement "However, I hope that this is not the smartest way to do it, and that there are smarter ways out there..." implies a request for advice. This site is best used once you have a specific problem that you can't figure out, general questions asking for guidance doesn't fit with SO's objectives. — itprorh66, Dec 17 '21 at 15:19
I can't figure out how to apply it onto an entire GeoDataFrame in an efficient manner. What I can do is individual shapes, but that is inefficient, it appears. I know that Geopandas allows for CRS changes, but I'm not sure which one to use and how to make that work... — stklik, Dec 17 '21 at 15:25

score 1 · Accepted Answer · answered Dec 17 '21 at 16:09

given your origin is EPSG:4326, you can estimate the UTM zone
with this you can get UTM zone coordinates of origin
translate your custom 200x200 metre zone into co-ordinates of UTM zone
finally use to_crs() to transform into EPSG:4326

import shapely.geometry
import geopandas as gpd
import pandas as pd
import numpy as np

# generate some polygons (squares), where grid is 200*200
gdf = gpd.GeoDataFrame(
    geometry=pd.DataFrame(
        np.repeat(np.sort(np.random.randint(0, 200, [20, 2]), axis=1), 2, axis=1)
    ).apply(lambda d: shapely.geometry.box(*d), axis=1)
)
# chage to linestrings, clearer when we plot
gdf["geometry"] = gdf["geometry"].exterior

origin = (2.350983211585546, 48.853772345870176)  # this is somewhere in Paris, for example

# work out utm crs of point.  utm is in metres
gdf_o = gpd.GeoDataFrame(geometry=[shapely.geometry.Point(origin)], crs="EPSG:4326")
crs = gdf_o.estimate_utm_crs()
# where is origin in utm zone
xo,yo = gdf_o.to_crs(crs).loc[0,"geometry"].xy

# translate custom zone to co-ordinates of utm zone
# assume point is center of 200x200 grid (hence subtract 100)
gdf_gps = gdf["geometry"].translate(xoff=xo[0]-100, yoff=yo[0]-100).set_crs(crs).to_crs("epsg:4326")

# plot on map to show it has worked...
m = gdf_gps.explore()
m = gdf_o.explore(m=m, color="red", marker_kwds={"radius":20})
m

This is exactly what I needed! Especially the `estimate_utm_crs` and the `translate` / `set_crs` / `to_crs` chain! — stklik, Dec 17 '21 at 16:26

project local coordinates to global GPS with reference point

1 Answers1