I am trying to create a simple logging in interface, where you can log in to change your information like email, username, password. The final piece of this puzzle for me is how can I send them back to the login screen after a lot of loops and steps:
package Exercises;
import java.util.ArrayList;
import java.util.Scanner;
import java.util.regex.Pattern;
import java.util.HashMap;
public class Final {
public static void main(String[] args) {
ArrayList<String> email = new ArrayList<String>();
HashMap<String, String> accounts = new HashMap<String, String>();
try (Scanner scan = new Scanner(System.in)) {
boolean n = true;
while(n){
System.out.println("1 - Login");
System.out.println("2 - Register");
String number1 = scan.nextLine();
switch(number1){
case "1":
boolean loginCheck = true;
while(loginCheck){
System.out.print("Enter username: ");
String userIn = scan.nextLine();
if(accounts.containsKey(userIn)){
System.out.print("Enter password: ");
String passIn = scan.nextLine();
if (passIn == accounts.get(userIn)) {
System.out.println("Welcome" + userIn + ", you can perform these actions: ");
System.out.println("1 - Change username");
System.out.println("2 - Change email");
System.out.println("3 - Change password");
System.out.println("4 - Log out");
System.out.println("0 - Exit");
String number2 = scan.nextLine();
switch (number2) {
case "0":
System.exit(0);
break;
case "1":
System.out.print("Type the new username: ");
String newUser = scan.nextLine();
accounts.remove(userIn);
accounts.put(newUser, passIn);
System.out.println("The username has been changed!");
break;
case "3":
System.out.print("Type the old email: ");
String oldMail = scan.nextLine();
System.out.print("Type the new email: ");
String newMail = scan.nextLine();
email.set(email.indexOf(oldMail), newMail);
System.out.println("Email has been changed!");
break;
case "4":
default:
break;
}
}
else{
System.out.println("Wrong password!");
System.out.println("1 - Try again");
System.out.println("2 - Forgot password");
String fpassCheck = scan.nextLine();
switch(fpassCheck){
case "1":
break;
case "2":
System.out.print("Type the email used to register: ");
String mailCheck = scan.nextLine();
if (email.contains(mailCheck)) {
System.out.print("Type the new passwor: ");
String newPass = scan.nextLine();
accounts.remove(userIn);
accounts.put(userIn, newPass);
System.out.println("Password has been changed.");
break;
}
else{
System.out.println("Account do not exist yet!");
break;
}
default:
break;
}
}
}
else{
System.out.println("Wrong username");
}
}
case "2":
System.out.print("Enter email: ");
String mailReg = scan.nextLine();
if(isValid(mailReg)){
if(email.contains(mailReg)){
System.out.println("There is already an existing account using this email!");
break;
}
else{
email.add(mailReg);
System.out.print("Create username: ");
String userReg = scan.nextLine();
boolean passCheck = true;
while (passCheck) {
String passRegex = "^(?=[A-Z])(?=.*[. , - _ ;]).{7,15}$";
Pattern pat = Pattern.compile(passRegex);
System.out.print("Tạo pasword: ");
String passReg = scan.nextLine();
if (pat.matcher(passReg).matches()) {
accounts.put(userReg, passReg);
passCheck = false;
}
else{
System.out.println("Password length must be between 7 and 15 characters, contains at least 1 uppercase, and 1 special character (. , - _ ;)");
}
}
}
}
else{
System.out.println("Incorrect Email, please try again.");
}
}
}
}
}
public static boolean isValid(String email)
{
String emailRegex = "^(.+)@(.+)$";
Pattern pat = Pattern.compile(emailRegex);
if (email == null)
return false;
return pat.matcher(email).matches();
}
}
After doing several actions, how can I make it so that it goes back to the login screen loop ? I assume that using multiple breaks is just really bad and might not even work properly.
