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I have link "https://uchebnik.mos.ru/app_player/204597". I need to get url with "https://learningapps.org/show.php?id=pxnu062wj20&fullscreen=1" or "pxnu062wj20". I have found this data in network: enter image description here

And in "sources" tab: enter image description here

It is desirable that this be done without using a webdriver. Also, i can use requests, requests_html, urllib3.

mooncdx
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  • That is great. However, what is your current progress on this? Could you post any code that you tried and it fails for some reason? – coldy Dec 24 '21 at 18:35
  • I don't have any code that relates to this. I tried to receive html page content, send GET requests, but I don't know how to get what I need. – mooncdx Dec 24 '21 at 18:38
  • You can try this yourself `https://docs.python-requests.org/en/latest/` – coldy Dec 24 '21 at 18:43
  • How can the link to the documentation of this module help me? I've already tried looking for answers but couldn't find anything. – mooncdx Dec 24 '21 at 18:50
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    We help you code, we don't do the coding for you. So please show your best attempt so we can help you out. Make sure to include a [minimal, reproducible example](https://stackoverflow.com/help/minimal-reproducible-example), now I get an error message when opening the site ("нет доступа к приложению") – RJ Adriaansen Dec 24 '21 at 18:56
  • @mooncdx, The documentation will help in getting started with a library to try something out yourself, rather than pushing the work to the fellow stackoverflow people to do for you. In terms of examples, you can take a look at other stackoverflow questions themselves: `https://stackoverflow.com/questions/1140661/what-s-the-best-way-to-get-an-http-response-code-from-a-url`, `https://stackoverflow.com/questions/18810777/how-do-i-read-a-response-from-python-requests` – coldy Dec 24 '21 at 19:39

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