Is there a way I can detect if there is any of a list inside of a string

Question

I have a variable called 'command' and I want to check whether command contains any of a certain list. For instance, if I have a list with ["a", "b", "c"] and I want to detect if command has any of those elements in it. So if command is "abc" it will return true for that if statement and if command is "ABC" it will return false.

Be careful that you don't run into the [Scunthorp problem](https://en.wikipedia.org/wiki/Scunthorpe_problem). — Mark Ransom, Dec 26 '21 at 17:03

tmarice · Answer 1 · 2021-12-26T21:19:09.730

3

def command_contains_element(command, element_list):
    return any(c in command for c in element_list)

edited Dec 26 '21 at 21:19

answered Dec 26 '21 at 16:52

tmarice

458
4
8

I don't understand the syntax for any(). What is the "for" and "in" for? – AgentStrawberry Dec 26 '21 at 17:42
1

Wouldn't it be `element_list` instead of `candidate_list` in the second line? – Syed Shahzer Dec 26 '21 at 18:01

Soyokaze · Answer 2 · 2021-12-26T17:09:54.443

-1

This might do the work:

isTrue = False
for i in ["a","b","c"]: #List you said
    if i in command: #command "abc"
        isTrue = True
        break
print(isTrue)

edited Dec 26 '21 at 17:09

answered Dec 26 '21 at 16:53

Soyokaze

157
8

1

This is going to print True or False 3 times, definitely not what the problem asked for. – Mark Ransom Dec 26 '21 at 17:05
Oh yeah thanks for pointing it out @MarkRansom – Soyokaze Dec 26 '21 at 17:10

Is there a way I can detect if there is any of a list inside of a string

2 Answers2