How do I output the result generated in if-loop as one array?

Question

I have my data as an array, and I want to extract every 7th value in the data. My code is like this:

import numpy as np

n=np.arange(0,100,1)
data=np.array(np.arange(0,100,1))

for n in n:
    if n%7==0:
        array=data[n]

But instead of one array, the 'array' in this output is actually a collection of single int objects(I would like to do this for float objects as well) that were looped over. How can I output one array or is if-loop not the way to do it?

have you tried [`numpy.ndarray.flatten`](https://numpy.org/doc/stable/reference/generated/numpy.ndarray.flatten.html)? — joshmeranda, Dec 28 '21 at 21:01
@joshmeranda Sorry, I should edit my post: I get a collection of single integer/float objects, not arrays. — Limona2000, Dec 28 '21 at 21:02

score 1 · Accepted Answer · answered Dec 28 '21 at 21:04

1

You can simply do this:

import numpy as np

n=np.arange(0,100,1)
data=np.array(np.arange(0,100,1))
data[::7]

for more informations: Understanding slice notation

answered Dec 28 '21 at 21:04

Constantin Guidon

1,892
16
21

Yes! That's exactly what I'm looking for. Thanks! – Limona2000 Dec 28 '21 at 21:05
The slice notation also seems very useful. I'll have a good read for sure. – Limona2000 Dec 28 '21 at 21:06
@Limona2000 if the answer is exactly what you need, consider accepting it ;) – mozway Dec 28 '21 at 21:30
1

@mozway Good call, just didd! Sorry, just started using this :) – Limona2000 Dec 28 '21 at 22:00

How do I output the result generated in if-loop as one array?

1 Answers1