Grep -v "Ready" without taking out "Not Ready"

Question

oc get serviceinstances | grep -v Ready

There are some results that are "Not Ready" but it would take them out as well because it looks for "Ready".

There are lots of different status names and "Ready" are the only ones I don't need.

For instance:

I need "Not Ready", "Error", "Failed"

@Ostone0 `grep -i 'ready' test | grep -vi 'not ready'`, maybe? — Renaud Pacalet, Jan 03 '22 at 15:22
The suggested duplicate question is not exactly a duplicate. — konsolebox, Jan 03 '22 at 15:22
@Tom S Please show the output of `oc get serviceinstances`. Please do this in your question, not in comments, external links, images... — Renaud Pacalet, Jan 03 '22 at 15:23
I think you're asking *not* to see Ready, so use `grep -E "Not Ready|Error|Failed"` — jarmod, Jan 03 '22 at 15:33
There are about 10+ different statues, so what I was asking is not to see "Ready" but anything else, including "Not Ready" — Tom S, Jan 03 '22 at 15:35
@TomS Please, never show text with images. They are not searchable, not copy-paste-able and much heavier than needed. Moreover they affect accessibility negatively. Please copy-paste the text in your question and [format it properly](https://stackoverflow.com/help/formatting), instead. And do not forget to indicate what is the field separator in the output of `oc get serviceinstances`. Tabs? Spaces? — Renaud Pacalet, Jan 03 '22 at 15:43

score 0 · Answer 1 · answered Jan 03 '22 at 15:42

0

When the fields are separated by tabs, use

oc get serviceinstances | grep -E "\tReady\t"

answered Jan 03 '22 at 15:42

Walter A

score 0 · Answer 2 · answered Jan 03 '22 at 15:51

0

Try

... | gawk '/\s+Not Ready\s+/ || !/\s+Ready\s+/'

answered Jan 03 '22 at 15:51

konsolebox

score 0 · Answer 3 · answered Jan 03 '22 at 16:27

0

oc get serviceinstances | egrep "Not Ready|Error|Failed"

answered Jan 03 '22 at 16:27

maryf

score 0 · Answer 4 · answered Jan 04 '22 at 02:18

0

If your grep supports -P (PCRE support) option, please try:

oc get serviceinstances | grep -v -P "(?<!Not )Ready"

The regex matches Ready unless it is preceded by Not , then the logic is negated by the -v option.

answered Jan 04 '22 at 02:18

tshiono

4 Answers4