This is the code I have used and it is not removing last zero it is skipping
x = [1,2,3,0,0,0]
for I in x:
if I==0:
x.remove(I)
print(x)
output:
[1, 2, 3, 0]
so from the output the last zero is not removing why
Asked
Active
Viewed 622 times
2
juanpa.arrivillaga
- 88,713
- 10
- 131
- 172
venkatesh babu E
- 21
- 1
-
As an aside, please always use the generic [python] tag for all python-related questions – juanpa.arrivillaga Jan 06 '22 at 15:51
2 Answers
1
Why don't you use this simple list comprehension.
x = [1,2,3,0,0,0]
y=[i for i in x if i != 0]
print(y)
You'll get a new list (y) with the 0 removed, while the x is preserved in it's original state.
[1, 2, 3]
Process finished with exit code 0
For more study on list.remove(), check this List.remove() does not remove all occurrances
Anand Gautam
- 2,018
- 1
- 3
- 8
1
As per documentation, list.remove removes first element whose value matches given number.
So, when first '0' at index 3 is removed, the new list is [1,2,3,0,0] with the list iteration index at 4. The following 0 (which was at index 4 in original list) moves back one place and is getting skipped. This can be seen with following code:
x = [0,0,0,0,0,0]
for id, i in enumerate(x):
print(id, i)
if i == 0:
print(x, i)
x.remove(i)
print(x)
In this, every second element is missed, and final x is [0, 0, 0]
As for what is correct way to do this, list comprehension is a good way, as answered by Anand: x = [i for i in x if i!=0]
