Nested list traversing in Python

Question

hello I am searching for this solution but couldn't find any

I want to convert below list

list1=[1,2,3,[4],5,[2,4]]

output=[1,2,3,4,5,2,4]

U got it with this code

list1=[1,2,3,[4],5,[2,4]]
list2=[]

for i in range(len(list1)):
    if type(list1[i])!=int:
        for j in range(len(list1[i])):
            list2.append(list1[i][j])
    else:
        list2.append(list1[i])
print(list2)

Can anyone tell any other way to this without for loops and all

You could look [here](https://stackoverflow.com/questions/952914/how-to-make-a-flat-list-out-of-a-list-of-lists) where similar topic has been discussed — baskettaz, Jan 07 '22 at 09:20

score -1 · Answer 1 · answered Jan 07 '22 at 09:20

-1

That could be a solution. Not the best one, but a solution :

list1 = [1, 2, 3, [4], 5, [2, 4]]
l = []
for i in list1:
    if type(i) is int:
        l.append(i)
    elif type(i) is list:
        for a in i:
            l.append(a)

Better :

list1 = [1, 2, 3, [4], 5, [2, 4]]
l = []
for i in list1:
    if type(i) is int:
        l.append(i)
    elif type(i) is list:
        l.extend(i)

answered Jan 07 '22 at 09:20

tCot

307
2
7

This will only work if the nesting level is limited. What if `list1 = [1, [[[[2]]]]]`? – hilberts_drinking_problem Jan 07 '22 at 09:22
I dont why but isnt's working in jupyter notebook – Gayatri Patil Jan 07 '22 at 17:34
i have to use list1 = [1, 2, 3, [4], 5, [2, 4]] l = [] for i in list1: if type(i) is int: l.append(i) elif type(i) is not int: l.extend(i) print(l) – Gayatri Patil Jan 07 '22 at 17:34
is not int , its not checkin for list data type if i use is list – Gayatri Patil Jan 07 '22 at 17:35

Nested list traversing in Python

1 Answers1