sort strings by string elements

Question

Need help for below scenario

000-2022, 000-2023, 005-2021, 000-2021, 003-2021, 004-2022, 007-2021

last 4 digits are year and middle 3 digits are priority number. I need this to be sorted with highest year first and below it should come the corresponding priority number of that years and then it should move on to the next lesser year.

expected result :

000-2023, 000-2022, 004-2022, 000-2021, 003-2021, 005-2021, 007-2021

Welcome to StackOverflow. Could you tell us what you have tried so far that didn't work? — Hubert Grzeskowiak, Jan 10 '22 at 03:18
What did you try so far? If you are lazy to google, please be informed this post will be flagged. — Md. Tazbir Ur Rahman Bhuiyan, Jan 10 '22 at 03:19
https://www.geeksforgeeks.org/how-to-sort-strings-in-javascript/ see this — Md. Tazbir Ur Rahman Bhuiyan, Jan 10 '22 at 03:21
Does this answer your question? [javascript sort array double sort](https://stackoverflow.com/questions/10403797/javascript-sort-array-double-sort) — A1exandr Belan, Jan 10 '22 at 03:32

score 1 · Answer 1 · answered Jan 10 '22 at 03:32

1

this way

let arr = ['000-2022', '000-2023', '005-2021', '000-2021', '003-2021', '004-2022', '007-2021']

arr.sort( (a,b)=>
  {
  let [aN,aY] = a.split('-').map(Number)
    , [bN,bY] = b.split('-').map(Number)
  return aY - bY || aN - bN  
  })

console.log(  arr )

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answered Jan 10 '22 at 03:32

Mister Jojo

20,093
6
21
40

Сondition check is rock! – A1exandr Belan Jan 10 '22 at 03:35

score 0 · Answer 2 · answered Jan 10 '22 at 03:23

Use the sort() function for sorting. And use the split() function to split the string.

let arr = ["000-2022", "000-2023", "005-2021", "000-2021", "003-2021", "004-2022", "007-2021"]
arr.sort((a,b)=>{
  let [aPriority,aYear] = a.split("-").map(it => Number(it));
  let [bPriority,bYear] = b.split("-").map(it => Number(it));
  return bYear > aYear ? 1 : 
         aYear > bYear ? -1 : 
         (aPriority - bPriority);
  
});
console.log(arr);

Hubert Grzeskowiak · Answer 3 · 2022-01-10T03:34:25.403

I would strongly recommend sanitising the input data first into a structured format. Then the sorting code will be much easier to understand.

Here's an example:

a = ["000-2022", "000-2023", "005-2021", "000-2021", "003-2021", "004-2022", "007-2021"]
structured = a.map((e) => {
  [priority, year] = e.split("-")
  return {priority, year}
})

// `sort()` changes the array in place, so there's no need for a new var
structured.sort((e1, e2) => {
  if (e1.year !== e2.year) {
    // year is different, so sort by that first
    return e1.year < e2.year && 1 || -1
  } else {
    // if year is the same, sort by priority
    return e1.priority < e2.priority && 1 || -1
  }
})
console.log(structured)

score 0 · Answer 4 · answered Jan 10 '22 at 03:31

Just use ordinary sort function

const data = ['000-2022', '000-2023', '005-2021', '000-2021', '003-2021', '004-2022', '007-2021']

const result = data.sort((item1, item2)=> {
  const [prior1, year1] = item1.split('-').map(Number);
  const [prior2, year2] = item2.split('-').map(Number);
  const yearRes = year2 - year1;
  
  return (yearRes === 0) 
    ? prior1 - prior2
    : yearRes  
})

console.log(result)

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sort strings by string elements

4 Answers4