How to get Python dictionary with the highest key value?

Question

I have a dictionary with latitude and longitude values passed from a different file.

absoluteList = {"latitude": absolute[1], "longitude": absolute[0]}

If we print absoluteList we get:

{'latitude': 507476711, 'longitude': -18299961}
{'latitude': 507447383, 'longitude': -18388366}
{'latitude': 507436793, 'longitude': -18459606}
{'latitude': 507427288, 'longitude': -18500804}
{'latitude': 507410993, 'longitude': -18521404}
{'latitude': 507395241, 'longitude': -18552732}
{'latitude': 507362921, 'longitude': -18550157}
{'latitude': 507344995, 'longitude': -18521404}

I need to print out the dictionary with the highest latitude value.

`max(absoluteList, key=itemgetter('latitude'))`. Imports: [`itemgetter()`](https://docs.python.org/3/library/operator.html#operator.itemgetter). — Olvin Roght, Jan 10 '22 at 16:28
Does this answer your question? [How do I sort a list of dictionaries by a value of the dictionary?](https://stackoverflow.com/questions/72899/how-do-i-sort-a-list-of-dictionaries-by-a-value-of-the-dictionary) — Olvin Roght, Jan 10 '22 at 16:35
@OlvinRoght getting this for both methods. TypeError: string indices must be integers — Artsiom Halash, Jan 10 '22 at 16:42
Then your input does not match with one which shown in question. — Olvin Roght, Jan 10 '22 at 16:43

score 1 · Answer 1 · answered Jan 10 '22 at 16:29

1

Just use max:

absoluteList = [
  {'latitude': 507476711, 'longitude': -18299961},
  {'latitude': 507447383, 'longitude': -18388366},
  {'latitude': 507436793, 'longitude': -18459606},
  {'latitude': 507427288, 'longitude': -18500804},
  {'latitude': 507410993, 'longitude': -18521404},
  {'latitude': 507395241, 'longitude': -18552732},
  {'latitude': 507362921, 'longitude': -18550157},
  {'latitude': 507344995, 'longitude': -18521404}
]

biggest_latitude = max(absoluteList, key=lambda x: x['latitude'])

{'latitude': 507476711, 'longitude': -18299961}

answered Jan 10 '22 at 16:29

Pedro Maia

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`lambda` is slower than `itemgetter()` – Olvin Roght Jan 10 '22 at 16:34
@OlvinRoght Yes, for performance use `itemgetter` like you said in the comments. – Pedro Maia Jan 10 '22 at 16:35

score 1 · Answer 2 · answered Jan 10 '22 at 16:30

1

print( max(absoluteList, key=lambda x: x['latitude']))

answered Jan 10 '22 at 16:30

Simon Hawe

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14

Better to use `itemgetter()`. – Olvin Roght Jan 10 '22 at 16:30

Tal Folkman · Answer 3 · 2022-01-10T16:42:40.517

0

The are 2 ways to do it is by

using itemgetter()

 from operator import itemgetter 
highest_value_in_list = max(absoluteList, key=itemgetter('latitude'))`

using max:

highest_value_in_list = max(absoluteList, key=lambda x: x['latitude'])

output:

{'latitude': 507476711, 'longitude': -18299961}

edited Jan 10 '22 at 16:42

answered Jan 10 '22 at 16:33

Tal Folkman

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How to get Python dictionary with the highest key value?

3 Answers3