how to get default saved request uri in grails spring security core 4?

Question

In grails 2.2 we could get the saved uri to redirect before login as follows. The redirect url would be saved in session[WebAttributes.SAVED_REQUEST].

def auth = {
    def config = SpringSecurityUtils.securityConfig
    def redirectURL
    DefaultSavedRequest defaultSavedRequest = session[WebAttributes.SAVED_REQUEST]
    def requestURI = defaultSavedRequest?.getRequestURI() ?: ''
    def contextPath = defaultSavedRequest?.contextPath ?: ''
    if (contextPath && requestURI.startsWith(contextPath)){
        requestURI = requestURI.substring(contextPath.length())
    }
    def id
    try{
        id = (requestURI =~ /^\/.*\/.*\/(\d+)/)[0][1]
    }
    catch(IndexOutOfBoundsException e){} // ignore
    if (requestURI.startsWith('/raceRegistration/registrationAuth') && id){
        defaultSavedRequest.parameterMap.id = id
        redirectURL = g.createLink(controller: 'stagedRaceRegistration', action: 'create', params: defaultSavedRequest.parameterMap)
    }

    if (springSecurityService.isLoggedIn()) {
        redirect uri: config.successHandler.defaultTargetUrl
        return
    }

    String view = 'auth'
    String postUrl = "${request.contextPath}${config.apf.filterProcessesUrl}"
    render view: view, model: [postUrl: postUrl,
                               rememberMeParameter: config.rememberMe.parameter,
                               requestParams: params.findAll{ key, value -> !key.matches('controller|action|id')},
                               skipUrl: redirectURL]
}

Is there a way to achieve the same in grails 4 and spring security core 4?

Here is what i did

I copied the Login controller class from the plugin to override auth method.

The default auth looks like this and i put the line DefaultSavedRequest defaultSavedRequest = session[WebAttributes.SAVED_REQUEST].

/** Show the login page. */
def auth() {

    def conf = getConf()

    if (springSecurityService.isLoggedIn()) {
        redirect uri: conf.successHandler.defaultTargetUrl
        return
    }


DefaultSavedRequest defaultSavedRequest = session[WebAttributes.SAVED_REQUEST]



    String postUrl = request.contextPath + conf.apf.filterProcessesUrl
    render view: 'auth', model: [postUrl: postUrl,
                                 rememberMeParameter: conf.rememberMe.parameter,
                                 usernameParameter: conf.apf.usernameParameter,
                                 passwordParameter: conf.apf.passwordParameter,
                                 gspLayout: conf.gsp.layoutAuth]
}

I get this error.

No such property: SAVED_REQUEST for class: org.springframework.security.web.WebAttributes. Stacktrace follows:

I read the documentation in full and couldnt find anything related to fetching saved request uri from session?

https://grails-plugins.github.io/grails-spring-security-core/snapshot/index.html

i appreciate any help. Thanks!

I think you are referring to a property that does not exist. Does `SpringSecurityUtils.SAVED_REQUEST` work? — Jeff Scott Brown, Jan 11 '22 at 13:48
If you have a reference to the session, you might use https://github.com/grails/grails-spring-security-core/blob/c714537385cac605c1b99b876c77ebf04c2bdfcb/plugin/src/main/groovy/grails/plugin/springsecurity/SpringSecurityUtils.groovy#L624-L626. — Jeff Scott Brown, Jan 11 '22 at 17:17

score 0 · Accepted Answer · answered Jan 12 '22 at 05:00

0

I ended up using this

    def savedrequest = SpringSecurityUtils.getSavedRequest(session)

    def requestURI = savedrequest.requestURI ?: ''
    def contextPath = savedrequest?.contextPath ?: ''

answered Jan 12 '22 at 05:00

kofhearts

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how to get default saved request uri in grails spring security core 4?

1 Answers1