Pass a specific argument in python and ignore the rest

Asked Jan 18 '22 at 15:54

Active Jan 18 '22 at 15:56

Viewed 34 times

I have a simple code that passes arguments in python as below

parser = argparse.ArgumentParser(description='Processing data')
parser.add_argument("-number" , required=True)
args = parser_args()

print('Hi your number is: ' + args.number)

so if I do python main.py -number 1234 it will print it for me.

What I want to do is if I add any other arguments like python main.py -blah -number 1234 I want to get the same result as before but right now it is showing me an error saying 'unrecognized arguments: -blah'

asked Jan 18 '22 at 15:54

Ray Palmer

1

@Verthais I imagine they want to ignore everything else, as the post title says. – Peter Wood Jan 18 '22 at 15:57
@Peter Wood like in https://stackoverflow.com/questions/12818146/python-argparse-ignore-unrecognised-arguments ? – Verthais Jan 18 '22 at 15:59
@PeterWood Yes I just found that too. Thank you! – Ray Palmer Jan 18 '22 at 16:01

Pass a specific argument in python and ignore the rest

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