Why when I ask for input of char first code work fine . But when I ask for input of integer value it does not ask for char input

Question

As you can see this code work fine when I ask for char input first It work without any problem.As you can see this code work fine when I ask for char input first It work without any problem.As you can see this code work fine when I ask for char input first It work without any problem.

#include<stdio.h>
int main(){
    char mathoperation;
    int num1,num2;
    printf("Give the math operation you want to use : ");
    scanf("%c",&mathoperation);
    printf("Give the first number of you opperation : ");
    scanf("%d",&num1);
    printf("Give the second number of you opperation : ");
    scanf("%d",&num2);
    
    switch (mathoperation)
    {
    case '+':
        printf("%d\n",num1+num2);
        break;
    case '-': 
        printf("%d\n",num1-num2);
        break;
    case '*':
        printf("%d\n",num1*num2);
        break;
    case '/':
        if(num2==0)
            printf("No you cant do that");
        else
            printf("%d\n",num1/num2);     
        break;
    case '%':
        printf("%d\n",num1%num2);
        break;
    default:
        printf("Error!");
        break;
    }
        return 0;
}

But when I ask for input for the integer value first it does not ask input for char. It directly go to defaut and print error.But when I ask for input for the integer value first it does not ask input for char. It directly go to defaut and print error.But when I ask for input for the integer value first it does not ask input for char. It directly go to defaut and print error.But when I ask for input for the integer value first it does not ask input for char. It directly go to defaut and print error.But when I ask for input for the integer value first it does not ask input for char. It directly go to defaut and print error.

#include<stdio.h>
int main(){
    char mathoperation;
    int num1,num2;
    printf("Give the math operation you want to use : ");
    scanf("%c",&mathoperation);
    printf("Give the first number of you opperation : ");
    scanf("%d",&num1);
    printf("Give the second number of you opperation : ");
    scanf("%d",&num2);
    
    switch (mathoperation)
    {
    case '+':
        printf("%d\n",num1+num2);
        break;
    case '-': 
        printf("%d\n",num1-num2);
        break;
    case '*':
        printf("%d\n",num1*num2);
        break;
    case '/':
        if(num2==0)
            printf("No you cant do that");
        else
            printf("%d\n",num1/num2);     
        break;
    case '%':
        printf("%d\n",num1%num2);
        break;
    default:
        printf("Error!");
        break;
    }
        return 0;
}

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`%d` strips leading whitespace, but `%c` does not. `\n` is a whitespace character. — William Pursell, Jan 18 '22 at 17:33
`scanf("%c",&mathoperation);` ==> `scanf(" %c",&mathoperation);` see the added space. — Weather Vane, Jan 18 '22 at 17:33
The `"%c"` does not do "ignore leading whitespace" thing. Try `" %c"`. **Better yet: forget `scanf()` exists and use `fgets()` for user input.** — pmg, Jan 18 '22 at 17:34
One space is a space, two spaces are whitespace. One space and one newline, or tab, etc, or any combination of one of them, or more, all together are whitespace. Placing a space before `%c` instructs `scanf` to remove ***all*** leading whitespace, not just one space. — Weather Vane, Jan 18 '22 at 17:42

Why when I ask for input of char first code work fine . But when I ask for input of integer value it does not ask for char input

0 Answers0