struct Foo {
val: i32
}
impl Foo {
pub fn maybe_get(&mut self) -> Option<&mut i32> {
Some(&mut self.val)
}
pub fn definitely_get(&mut self) -> &mut i32 {
{ // Add closure to ensure things have a chance to get dropped
if let Some(val) = self.maybe_get() {
// Explicit return to avoid potential scope sharing with an else block or a match arms.
return val;
}
}
// One would think any mutable references would not longer be at play at this point
&mut self.val
}
}
I have some code that's similar but more complicated than what is provided above that I've been fighting with for quite a while. The borrow checker is unhappy with the implementation of definitely_get
and has the following error
error[E0499]: cannot borrow `self.val` as mutable more than once at a time
--> src/main.rs:19:9
|
10 | pub fn definitely_get(&mut self) -> &mut i32 {
| - let's call the lifetime of this reference `'1`
11 | {
12 | if let Some(val) = self.maybe_get() {
| ---------------- first mutable borrow occurs here
13 | return val;
| --- returning this value requires that `*self` is borrowed for `'1`
...
19 | &mut self.val
| ^^^^^^^^^^^^^ second mutable borrow occurs here
It seems unreasonable for there to be no way to implement fallback logic with a mutable reference in Rust so I can't imagine there isn't a way.